Home
Class 12
MATHS
Find the sum of the last 30 coefficients...

Find the sum of the last 30 coefficients in the expansion of `(1+x)^(59),` when expanded in ascending powers of `xdot`

Text Solution

Verified by Experts

The correct Answer is:
`2^(58)`

There are 60 terms is the expansion of `(1+x)^(59)`. Sum of last `30` coefficient is
`S = .^(59)C_(30) + .^(59)C_(31) + "….." + .^(59)C_(58) + .^(59)C_(59)`
`:. S = .^(59)C_(29) + .^(59)C_(28) + "……." + .^(59)C_(1) + .^(59)C_(0)` [Using `.^(n)C_(r ) = .^(n)C_(n-r)`]
Adding the above two expansions, we get
`2S = .^(59)C_(0) + .^(59)C_(1) + "......" + .^(59)C_(59) = 2^(59)`
or `S = 2^(58)`
Promotional Banner

Topper's Solved these Questions

  • BINOMIAL THEOREM

    CENGAGE|Exercise Exercise 8.5|8 Videos
  • BINOMIAL THEOREM

    CENGAGE|Exercise Exercise 8.6|10 Videos
  • BINOMIAL THEOREM

    CENGAGE|Exercise Exercise 8.3|7 Videos
  • AREA UNDER CURVES

    CENGAGE|Exercise Question Bank|20 Videos
  • BINOMIAL THEORM

    CENGAGE|Exercise Question Bank|31 Videos

Similar Questions

Explore conceptually related problems

Let S be the sum of the last 24 coefficients in the expansion of (1 + x)^(47) when expanded in ascending powers of x, then (S-2^(44))/(2^(44)) =____

If sum of the last 30 coefficients in the expansion of (1+x)^59, when expanded in ascending power of 'x' is 2^n then number of divisors of 'n' of the form 4lambda+ 2(lambda in N) is (A)1 (B)0 (C)2 (D) 4

The sum of the last eitht coefficients in the expansion of (1 + x)^(15) , is

Find the sum of the coefficients in the expansion of (7+4x)^(49)

What is the sum of the coefficients in the expansion of (1+x)^(n) ?

What is the sum of the binomial coefficients in the expansion of (1+x)^(50)

What is the sum of all the coefficients in the expansion of (1+x)^(n) ?