A binary number is made up to 8 digits. Suppose that the probability if an incorrect digit appearing is `p` and that the errors in different digits are independent of each other. Then find the probability of forming an incorrect number.

Answer

`1-(1-p)^(8)`

Explanation

Probability for an incorrec digit is p. hence, probability for 8 correct digit is `1-p)^(8).` Hence, required probability is `1-(1-p)^(8).`