When a ship is sailing in ocean where temperature is `30^(@)C` , a baloon is filled with `4.0 L` of air. What will be the volume of the ballon when the ship reaches other ocean, where temperature is `33^(@)C`.

Explanation

`T_(1)=30^(@)C=30+273*15=303*15 K, T_(2)=33^(@)C=33+273*15=306*15K`
Apply Charle.s law , `(V_(1))/(T_(1))=(V_(2))/(T_(2))=(4*0(L)xx306.15K)/(303*15K)=4*039L`
`:. V_(2)=4*039L`