Calculate the number of moles of hydrogen present in `500 cm^(3)` of a gas under a pressure of `101.3 ` kPA at a temperature of `300K`. (`R=8.314 J K^(-1) mol^(-1))`.

Explanation

`n=?, V=500 cm^(3) =500x10^(-3) dm^(3)=0*5 dm^(3)`
`T=300K`
`PV= nRT or n=(PV)/(RT)=(101*3xx0*5)/(8*314xx300)=0*203 "mol"`
`:. n=0*0203` mol