What will be the minimum pressure required to compress `500 dm^(3)` of air at 1 bar to 200 `dm^(3)` at `30^(@)C?`

Explanation

Thus, `P_(1)= 1 "bar" P_(2) = ?`
`v_(1)=500 dm^(3) " " v_(2)=200 dm^(3)`
Temperature remain constant
According to Boyle.s law
`P_(1)v_(1)=P_(2)v_(2) or P_(2) =(P_(1)v_(1))/(v_(2))`
`p_(2)=(1 "bar" xx500 dm^(3))/(200 dm^(3))=2*5 "bar"`