A vessel of 120 mL capacity contains a certain amount of gas at `35^(@)C` and 1.2 bar pressure. The gas 1p transferred to another vessel of volume 180 mL at `35^(@) C`. What would be its pressure ?

Explanation

`P_(1)=1*2` bar `P_(2) =?, v_(1)=120 mL, v_(2)=180 mL`
Temperature contant.
According contant.
According to Boyle.s law `P_(1)V_(1)=P_(2)V_(2) `or
`P_(2) =(P_(1)V_(1))/(V_(2))=(1*2 "bar" xx12 mL)/(180mL)=0*8 "bar"`.