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34.95 mole of phosphorus vapour weighs 0...

`34.95` mole of phosphorus vapour weighs `0.0625g ` at 0.1 bar pressure. What is the molar mass of phosphorus ?

Text Solution

Verified by Experts

According to ideal gas equation.
`Pv= nRT`
Now, `n=(W)/(M):. Pv=(WRT)/(M) or M=(WRT)/(PV)`
Substituting the values of from data
`M=(0*0625gxx0*83 "bar" L K^(-1) "mol"^(-1) xx819*15K)/(1"bar" xx34*04xx10^(-3)L)`
`:. M=124*8 g "mol"^(-1)`
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