The value of Ionic Product of water at 298 K is `1xx10^(-14)`, what is its `[H^(+)]` ?

Give the value of ionic product of pure water at 298 K.

What is meant by ionic product of water (K_(w)) ?

Derive the ionic product of water and give its value at 25^(@)C .

Derive ionic product of water. Also find its value at 25^(@)C .

Henry 's law constant for the solubility of N_(2) gas in water at 298 K is 1.0 xx 10^(5) atm . The mole fraction of N_(2) in air is 0.6 . The number of moles of N_(2) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is a. 3.0 xx 10^(-4) b. 4.0 xx 10^(-5) c. 5.0 xx 10^(-4) d. 6.0 xx 10^(-6)

Solubility product of PbCl_(2) at 298 K is 1.0xx10^(-6) . At this temperature solubility of PbCl_(2) in moles per litre is :