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A buffer solution of pH 8.3 is prepared ...

A buffer solution of pH 8.3 is prepared from ammonium chloride and ammonium hydroxide. Dissociation constant of ammonium hydroxide is `1.8xx10^(-5)`. What is the mole proportion of ammonium chloride and ammonium hydroxide?

Text Solution

Verified by Experts

`pOH=14-pH=14-8.3=5.7`
`pH=pK_(a)+log(["salt"])/(["acid"])=pH=-log_(10)K_(a)+"log"(["salt"])/(["base"])`
`5.7=-log_(10)(1.8xx10^(-5))+"log"([NH_(4)Cl])/([NH_(4)OH])implies5.7=-5-log1.8+"log"([NH_(4)Cl])/([NH_(4)OH])`
`5.7=5-0.2553+"log"([NH_(4)Cl])/([NH_(4)OH])implies5.7=4.7447"log"([NH_(4)Cl])/([NH_(4)OH])`
`:."log"([NH_(4)Cl])/([NH_(4)OH])=5.7-4.7447=0.9553`
`implies ([NH_(4)Cl])/([NH_(4)OH])=` antilog (0.9553)=9.022. The ratio is 9:1.
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