Calculate the solubility of `A2xx3` pure water. Assuming that neither king of ion reacts with water. The solubility product of `A2X3Ksp=1.1xx10-23`
Explain with equation.

Explanation

`k_(sp)=[A^(3+)]^(2)[X^(-2)]^(3)=[2s]^(2).[3s]^(3)=108s^(5)`
`S^(5)=(1.1xx10^(-23))/108=1xx10^(-25)`
`S^(5)=1xx10.5"mol"dm^(-3)`