Home
Class 12
CHEMISTRY
Silver crystallizes in CCP lattice. The ...

Silver crystallizes in CCP lattice. The edge length of its unit cell is 408.6 pm. Calculate density of silver (atomic mass of silver is 107.9)

Text Solution

Verified by Experts

here, `Z=4, a=408.6xx10^(-12)m`
`:.d=(ZxxM)/(a^3xxN_A)=(4xx108)/((408.6xx10^(-12))^3xx6.023xx10^(23))=10.5g//cm^3`
Promotional Banner

Topper's Solved these Questions

  • ANNUAL EXAM QUESTION PAPER WITH ANSWER MARCH(2016)

    SUBHASH PUBLICATION|Exercise PART E|16 Videos

  • ANNUAL EXAM QUESTION PAPER WITH ANSWER MARCH(2016)

    SUBHASH PUBLICATION|Exercise PART C|15 Videos

  • ANNUAL EXAM QUESTION PAPER MARCH 2017

    SUBHASH PUBLICATION|Exercise PART D|11 Videos

  • ANNUAL EXAMINATION QUESTION PAPER MARCH - 2018

    SUBHASH PUBLICATION|Exercise V. Answer any four of the following . Each question carriers five marks.|17 Videos

Similar Questions

Explore conceptually related problems

Silver forms ccp lattice and x-ray studies of its crystals show that the edge length of its unit cell is 408.6 pm. Calculate the density of silver. (Atomic mass of Ag = 107.9 u)

Silver froms ccp lattice and X -ray studies of its crystals show that the edge length of its unit cell is 408.6 pm. Calculate the density of silver (atomic mass = 107.9 u ).

a. Calculate the packing efficiency in a Body Centered Cubic (BCC) lattice. b. Silver forms a ccp lattice. The edge length of its unit cell is 408.6 pm. Calculate the density of silver. (N_(A)=6.022xx10^(23)," Atomic mass of Ag "=108 g mol^(-1))

b) An element crystallizes in a foc lattice. The edge length of the unit cell is 400 pm. Calculate the density of the unit cell. ("molar mass"="60 g mol"^(-1)) ("Avogadro number"=6.02 xx 10^(23))

The edge length of NaCl unit cell is 564 pm. The density of NaCl in gcm^-3 is

An element having atomic mass 107.9 u has FCC lattice. The edge length of its unit cell is 408.6 pm. Calculate density of the unit cell. ["Given, "N_(A)=6.022xx10^(23)"mol"^(-1)] .

An element crystallizes in fcc lattice. If the edge length of the unit cell is 408.6 pm and the density is 10.5 g cm^(-3) . Calculate the atomic mass of the element.

An element crystallized in fcc lattice and edge length of unit cell is 400 pm. If density of unit cell is 11.2 g cm^(-3) , then atomic mass of the element is