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5.8 g of non - volatile, non - electroly...

5.8 g of non - volatile, non - electrolyte solute was dissolved in 100 g of carbon disuiphide `(CS_(2))`. The vapour pressure of the solution was found to be 190 mm of Hg. Calculate molar mass of the solute. Given : Vapour of pure `CS_(2)` is 195 mm of Hg and molar mass of `CS_(2)` is `76g//mol`.

Text Solution

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`(P^0-p)/(P^0)=(W_2M_1)/(M_2W_1)`
`(195-190)/(195)=(5.8xx76)/(M_2)=17.19gm01^(-1)`
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