Find `(dy)/(dx)fory=xsinxlogxdot`

Explanation

We have
`(d)/(dx) (x sin x log x)`
`={(d)/(dx)(x)}sin x log x+x{(d)/(dx)(sin x)} log x + x sin x{(d)/(dx) (log x)}`
`=1xxsinxxlog x + x xx cos x xx log x + x xx sin x xx(1)/(x)`
`=sin x log x + x cos x log x + sin x`