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y=e^(sin x^(3))...

`y=e^(sin x^(3))`

Text Solution

Verified by Experts

The correct Answer is:
`e^(sin x^(2))cos x^(2)2x`
`"Let "y=e^(sinx^(2)).`
Putting `x^(2)=v and u=sin x^(2) = sin v,` we get
`y=e^(u),u=sin v, and v=x^(2)`
`therefore" "(dy)/(du)=e^(u),(du)/(dv)=cos v, and (dv)/(dx)=2x`
`"Now, "(dy)/(dx)xx(dy)/(du)xx(du)/(dv)xx(dv)/(dx)`
`=e^(u)cos v 2=e^(sin v)cos v 2x`
`=e^(sin x^(2))cos x^(2)2x`
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