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If g is the inverse function of and f'(x...

If g is the inverse function of and f'(x) = sin x then prove that g'(x) = cosec (g(x))

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Since g is the inverse function of f, we have f(g(x))=x
`rArr" "(d)/(dx)(f(g(x)))=1`
`rArr" "f'(g(x)).g'(x)=1`
`rArr" "g'(x)=(1)/(sin {g(x)})`
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