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A hammer of mass 500 g, moving at 50ms^...

A hammer of mass 500 g, moving at `50ms^(-1)` strikes a nail.
The nail stops the hammer in a very short time of 0.01s.
what is the force of the nail on the hammer.

Text Solution

Verified by Experts

Mass of the harmmer , m=500 g =0.5 kg. Initial velocity of the hammer,u=50 m/s. time taken by the nail to stop the hammer t=0.01 s
Velocity of the hammer, v=o (Since the hammer finally comes to rest)
From Newton.s second law of motion
Force f=m(v-u)/t
`=0.5 (0-50)/0.01`
=-2500 N
The hammer strikes the nail with a force of -2500 N . Hence from newton.s third law of motion, the force of the nail on the hammer is equal and opposite i.e,+2500 N
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