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[NiCl(4)]^(2-) is paramagnetic while [Ni...

`[NiCl_(4)]^(2-)` is paramagnetic while `[Ni(CO)_(4)]` is diamgnetic though both are tetrahedral. Why ?

Text Solution

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In `Ni(CO)_(4)`, Ni is in zero oxidation state whereas in `NiCl_(4)^(2-)`, it is in `+2` oxidation state. In the presence of CO ligand, the unpaired d electrons of `Ni` pair up but `Cl-` being a weak ligand is unable to pair up the unpaired electrons.
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