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When forces F(1) , F(2) , F(3) are actin...

When forces `F_(1)` , `F_(2)` , `F_(3)` are acting on a particle of mass m such that `F_(2)` and `F_(3)` are mutually prependicular, then the particle remains stationary. If the force `F_(1)` is now rejmoved then the acceleration of the particle is

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If mass .m. is stationary under three forces,
`vec(F_(1))+vec(F_(2))+vec(F_(3))=0`
`vec(F_(1))=-(vec(F_(2))+vec(F_(3)))`
`sqrt(F_(2)^(2)+F_(3)^(2))=F_(1)`
Obviously if `F_(1)` is removed then the mass will have acceleration, `a=(sqrt(F_(2)^(2)+F_(3)^(2)))/(m)`
(or) `a=(F_(1))/(m)`
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NARAYNA-LAW OF MOTION-EXERCISE - IV
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  10. The pulley arrangements shown in figure are identical, the mass of the...

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  11. A string of negligible mass going over a clamped pulley of mass m supp...

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  16. Fig. shows a block of mass m(1) resting on a smooth surface. It is con...

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