A ball hits a floor normally with velocity u and return with same speed. If the ball is in contact with the floor for 0.1 sec, find the average impulsive force acting on the ball. Take the mass of the ball m = 200 gm and `u=2m//s.`

Explanation

Force on the ball :
`"Average impulsive force, "`
`vecF=(DeltavecP)/(Deltat)rArr" "F=(2m u)/(Deltat)=(2(0.2)2)/(0.1)=8N`
Hence, force on of the ball is 8 N upwards. The force on the floor by the ball is 8 N downwards.