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A mass M is suspended by a weightless st...

A mass `M` is suspended by a weightless string The horizontal force required to hold the mass `60^(@)` with the vertical is .

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`F=T sin theta" ……..(1)"`
`Mg=T cos theta" ……..(2)"`
Dividing Eq. (1) and Eq. (2)
`(F)/(Mg)=(T sin theta)/(T cos theta), F=Mg tan theta`
`F=Mg tan 60^(@), F=sqrt3Mg`
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NARAYNA-LAW OF MOTION-EXERCISE - IV
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