A chain of mass 'm' is attached at two points `A` and `B` of two fixed walls as shown in the Find the tension in the chain near the walls at point `A` and at the mid point `C`
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Explanation

i) At point C
`2Tsin theta=mg rArr T=(1)/(2) mg " cosec "theta`
ii) Tension along horizontal direction is same every - where
`because ` (no external force is acting on it in horizontal direction.
At point A
`T^(1)=T cos theta =(mg cos theta)/(2 sin theta)=(mg cot theta)/(2)`