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By what acceleration the boy must go up ...

By what acceleration the boy must go up so that 100 kg block remains stationary on the wedge. The wedge is fixed and is smooth.`(g=10m//s^(2))`

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For the block to remain stationary,
`T=Mg sin theta=100xx10xxsin 53`
`=100xx10xx(4)/(5)=800N`
For man, `T-mg=ma`
`T=m(g+a)rArr 800=50(10+a)a=6m//s^(2)`
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