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A block of mass 10 kg is suspended with ...

A block of mass 10 kg is suspended with two strings as shown in the fig. Find the tensions `T_(1) and T_(2)` in the two string.

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The free body diagram of the joint O is drawn as shown in fig.
Applying equation for equilibrium.
`SigmaF_(x)=0" "T_(2)sin30^(@)-t_(1)=0" ……(i)"`
`SigmaF_(y)=0" "T_(2)cos 30^(@)-100=0" ….(ii)"`
`"Thus "T_(2)=(100)/(cos30^(@))=(200)/(sqrt3)N`

Substituting the value of `T_(2)` in equation (i), we get `T_(1)=T_(2) sin 30^(@)=(100)/(sqrt3)N`
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NARAYNA-LAW OF MOTION-EXERCISE - IV
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