A particle moves in a circular path of radius `0.5 m` at a speed that uniformly increases. Find the angular acceleration of particle if its speed changes from `2.0m//s` to `4.0 m//s` in `4.0s`

Explanation

The tangential acceleration of the particle is
`a_(t)=(Deltavecv)/(dt)=(4.0-2.0)/(4.0)=0.5m//s^(2)`
The angular acceleration is `alpha=(a_(t))/(r )=(0.5)/(0.5)=1" rad/s"^(2)`