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A body is undergoing circular motion. So...

A body is undergoing circular motion. Some vector expression that describe the motion are given below
(a) `vecV=vecomega xx vecR`
(b) `a_(vecT)=vec alpha xx vecR`
(c ) `a_(vecC)=vecalphaxx vecR`
Of the above statements following are/is correct

A

a, b and c

B

a and b

C

b and c

D

c and a

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given vector expressions related to circular motion and determine which of them are correct. Let's break down the statements one by one. ### Step 1: Analyze Statement (a) The first statement is: \[ \vec{V} = \vec{\omega} \times \vec{R} \] Where: - \(\vec{V}\) is the linear velocity vector. - \(\vec{\omega}\) is the angular velocity vector. - \(\vec{R}\) is the radial vector (position vector from the center of the circular path to the particle). In circular motion, the linear velocity \(\vec{V}\) of a particle is indeed given by the cross product of the angular velocity \(\vec{\omega}\) and the radial vector \(\vec{R}\). This statement is correct. ### Step 2: Analyze Statement (b) The second statement is: \[ \vec{a}_{\text{T}} = \vec{\alpha} \times \vec{R} \] Where: - \(\vec{a}_{\text{T}}\) is the tangential acceleration vector. - \(\vec{\alpha}\) is the angular acceleration vector. Tangential acceleration is related to the change in angular velocity over time. The correct expression for tangential acceleration is given by: \[ \vec{a}_{\text{T}} = \alpha \cdot \vec{R} \] This means that the tangential acceleration is directly proportional to the angular acceleration and not through a cross product. Therefore, this statement is incorrect. ### Step 3: Analyze Statement (c) The third statement is: \[ \vec{a}_{\text{C}} = \vec{\alpha} \times \vec{R} \] Where: - \(\vec{a}_{\text{C}}\) is the centripetal acceleration vector. Centripetal acceleration is directed towards the center of the circular path and is given by: \[ \vec{a}_{\text{C}} = \frac{V^2}{R} \text{ (or equivalently, } \frac{\omega^2 R}{R} = \omega^2 R\text{)} \] It is not expressed as a cross product with angular acceleration. Therefore, this statement is also incorrect. ### Conclusion From the analysis: - Statement (a) is **correct**. - Statement (b) is **incorrect**. - Statement (c) is **incorrect**. Thus, the correct statements are: - Only statement (a) is correct. ### Final Answer The correct answer is: **Only statement (a) is correct.**
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