Home
Class 11
PHYSICS
A small sphere of mass m =2kg moving wit...

A small sphere of mass `m =2kg` moving with a velocity `baru = 4hati - 7hatj m//s` colides with a smooth wall and returns with a velocity `barv = -hati + 3hatj m//s`. The magnitude of the impulse received by the ball is .

A

`5kgms^(-1)`

B

`10sqrt5kkgms^(-1)`

C

`20kgms^(-1)`

D

`115kgms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`J=m(v-u)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - I (C.W)(OBJECTS SUSTENDED BY STRINGS & APPARENT WEIGHT)|9 Videos

  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - I (C.W)(LAW OF CONSERVATION OF MOMENTUM)|3 Videos

  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - I (C.W)(NEWTON.S LAWS OF MOTION)|8 Videos

  • KINETIC THEORY OF GASES

    NARAYNA|Exercise LEVEL-III(C.W)|52 Videos

  • MATHEMATICAL REVIEW & PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|13 Videos

Similar Questions

Explore conceptually related problems

A small sphere of mass m =1 kg is moving with a velocity (4hati-hatj) m//s . it hits a fixed smooth wall and rebounds with velocity (hati + 3hatj) m//s . The coefficient of restitution between the sphere and the wall is n//16 . Find the value of n .

A particle of mass m moving with a velocity (3hati+2hatj)ms^-1 collides with another body of mass M and finally moves with velocity (-2hati+hatj)ms^-1 . Then during the collision

Knowledge Check

  • A small sphere of mass 1kg is moving with a velocity (6hati+hatj)m//s . It hits a fixed smooth wall and rebounds with velocity (4hati+hatj)m//s . The coefficient of restitution between the sphere and the wall is

    A
    `(3)/(2)`
    B
    `(2)/(3)`
    C
    `(9)/(16)`
    D
    `(4)/(9)`

  • A ball of mass 1 kg moving with velocity vecv = 3hati + 4 hatj collides with a wall and after collision velocity of the ball is -2 hati + 6 hatj . Which of the following unit vectors is perpendicular to wall?

    A
    `1/5 (-3hati - 4hatj)`
    B
    `1/(sqrt(29))(5 hati + 2 hatj)`
    C
    `1/(sqrt(40)) -(2 hati + 6 hatj)`
    D
    `1/(sqrt(40))(5 hati - 2hatj)`

  • A particle moving with a velocity of ( 4hati-hatj ) mis strikes a fixed smooth wall and finally moves with a velocity of ( 3hati + 2hatj ) m/s. The coefficient of restitution between the wall and the particle in the collision will be

    A
    `7/3`
    B
    `3/7`
    C
    `sqrt(13/17)`
    D
    `sqrt(17/13)`

    • Similar Questions

    Explore conceptually related problems

    A cricket ball of mass 100g has initial velocity vec u = (3hati + 4hatj)ms and final velocity vec v = (-3hati -4hatj)ms after being hit by the bat.The magnitude of the impulse on the bat by the ball will be

    A block of mass 2 kg is moving with a velocity of 2hati-hatj+3hatk m/s. Find the magnitude and direction of momentum of the block with the x-axis.

    A particle of mass 1.0 g moving with a velocity vecv_1 = (3hati - 2hatj) m/s experiences a perfectly inelastic collision with another particle of mass 2.0 g and velocity vecv_2 = (4hati - 6hatj) m/s. Find the magnitude of the velocity vector vecv of the coalesced particles.

    A body of mass 3 kg moving with a velocity (2hati+3hatj+3hatk) m/s collides with another body of mass 4 kg moving with a velocity (3hati+2hatj-3hatk) m/s. The two bodies stick together after collision. The velocity of the composite body is

    A body of mass m moving with velocity u hati collides elastically with a body at rest of mass 3m and then the final velocity of body mass m is v hatj . Find the relation between v and u

    Home
    Profile