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A 0.2 kg object at rest is subjected to ...

A 0.2 kg object at rest is subjected to a force `(0.3hati – 0.4hatj)N`. What is its velocity vector after 6 sec

A

`(9hati-12hatj)`

B

`(8hati-16hatj)`

C

`(12hati-9hatj)`

D

`(16hati-8hatj)`

Text Solution

Verified by Experts

The correct Answer is:
A
`veca=(vecF)/(m), vecv=vecu+vecat`
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