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A 20 kg body is pushed with a force of 7...

A 20 kg body is pushed with a force of 7N for 1.5 sec then with a force of 5N for 1.7 sec and finally with a force of 10N for 3 sec, the total impulse applied to the body and change in velocity will be

A

`49Ns,12.5ms^(-1)`

B

`49Ns,2.45ms^(-1)`

C

`98Ns,4.9ms^(-1)`

D

`4.9Ns,2.45ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`J=Fxxt, J=F_(1)t_(1)+F_(2)t_(2)+F_(3)t_(3), J=m(v-u)`
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