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Three bodies are lying on a frictionless...

Three bodies are lying on a frictionless horizontal table and these are connected as shown in the figure. They are pulled towards right with a force `T_(3) = 60N` If `m_(1), m_(2)and m_(3)`, are equal to 10 kg, 20kg and 30kg respectively, then the values of `T_(1)` and `T_(2)` will be

A

`10N,10N`

B

`30N,10N`

C

`10N,30N`

D

`10N,10N`

Text Solution

Verified by Experts

The correct Answer is:
C
`T_(3)-T_(2)=m_(3)a,`
`T_(2)-T_(1)=m_(2)a, T_(1)=m_(1)a, a=(T_(3))/(m_(1)+m_(2)+m_(3))`
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