Home
Class 11
PHYSICS
A block of mass 5kg is lying on a rough ...

A block of mass 5kg is lying on a rough horizontal surface. The coefficient of static and kinetic friction are 0.3 and 0.1 and `10m//s^(-2)`. If a horizontal force of 50N is applied on the block, the frictional force is

A

25N

B

5N

C

10N

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
B

`f_(s)=mu_(S)N, f_(k)=mu_(k)N, N=mg`
Promotional Banner

Topper's Solved these Questions

  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - I (H.W)(MOTION OF A BODY ON THE INCLINED PLANE)|5 Videos
  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - I (H.W)(CIRCULAR MOTION)|3 Videos
  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - I (H.W)(LAWS OF FRICTION)|2 Videos
  • KINETIC THEORY OF GASES

    NARAYNA|Exercise LEVEL-III(C.W)|52 Videos
  • MATHEMATICAL REVIEW & PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|13 Videos

Similar Questions

Explore conceptually related problems

A block of mass 5 kg is lying on a rough horizontal surface. The coefficient of static and Kinetic friction are 0.3 and 0.1 and g=10m//s^(-2) If a horizontal force of 50N is applied on the block, the frictional force is

The block of mass 4kg is placed on a rough horizontal surface having the coefficient of kinetic and static friction as 0.4 and 0.5 respectively. If a force of 4N is applied to the body, then the frictional force acting on the body will be [g= m/s^2 ]

A body of mass 2 kg is placed on a horizontal surface having coefficient of kinetic friction 0.4 and limiting coefficient of static friction 0.5. If a horizontal force 2.5 N is applied on the body, the frictional force acting on the body will be (Take, g = 10ms^(2) )

A block of mass 2kg is resting on a rough horizontal surface.The coefficients of static and kinetic frictions between the block and surface are 0.7 and 0.6 respectively.A horizontal force F=(4N/s)times t is applied on the block at t=0.At t=4s ,the force of friction on the block is (take g=10m/s^(2) )

A block of mass 4 kg is kept on a rough horizontal surface. The coefficient of static friction is 0.8. If a force of 19 N is applied on the block parallel to the floor, then the force of friction between the block and floor is

A block of mass 20kg is pushed with a horizontal force of 90N . It the coefficient of static and kinetic friction are 0.4 and 0.3, the frictional force acting on the block is (g =10ms^(-2)) .

A block of mass 2 kg is at rest on a floor . The coefficient of static friction between block and the floor is 0.54. A horizonatl force of 2.8 N is applied to the block . What should be the frictional force between the block and the floor ? ( take , g = 10 m//s^(2) )