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The coefficient of friction between a he...

The coefficient of friction between a hemispherical bowl and an insect is `sqrt(0.44)` and the radius of the bowl is 0.6m. The maximum height to which an insect can crawl in the bowl will be

A

0.4m

B

0.2m

C

0.3m

D

0.1m

Text Solution

Verified by Experts

The correct Answer is:
D
`h=r(1-cos theta)=r[-(1)/(sqrt(mu_(s)^(2)+1))]`
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Knowledge Check

  • The coefficient of friction between an insect and a hemispherical bowl of radius r is mu . The maximum height to which the insect can crawl in the bowl is

    A
    `( r )/( sqrt( 1+ mu^(2)))`
    B
    `r[1-(1)/( sqrt( 1+ mu^(2)))]`
    C
    `r sqrt( 1+ mu^(2))`
    D
    `r[ sqrt( 1+ mu^(2))-1]`

  • The coefficient of friction between two surface is 0.2. The maximum angle of friction is

    A
    `sin^(-1)(0.2)`
    B
    `cos^(-1)(0.2)`
    C
    `tan^(-1)(0.1)`
    D
    `cot^(-1)(5)`

  • A particle is placed at rest inside a hollow hemisphere of radius R. The coefficient of friction between the particle and the hemisphere is mu=(1)/(sqrt(3)) . The maximum height up to which the particle can remain stationary is

    A
    `(R )/(2)`
    B
    `(1-(sqrt3)/(2))R`
    C
    `(sqrt3)/(2)R`
    D
    `(3R)/(8)`