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A duster weighs 0.5N. It is pressed agai...

A duster weighs 0.5N. It is pressed against vertical board with a horizontal force of 11N. If the co-efficient of friction is 0.5 the minimum force that must be applied on the duster parallel to the board to move it upwards is

A

0.4 N

B

0.7 N

C

6N

D

7N

Text Solution

Verified by Experts

The correct Answer is:
C
`F_(up)=f+mg, f=muN, N=F`
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