Home
Class 11
PHYSICS
A vehicle of mass M is moving on a rough...

A vehicle of mass M is moving on a rough horizontal road with a momentum P. If the coefficient of friction between the tyres and the road is `mu`, then the stopping distance is

A

`(P)/(2muMg)`

B

`(P^(2))/(2muMg)`

C

`(P^(2))/(2muM^(2)g)`

D

`(P)/(2muM^(2)g)`

Text Solution

Verified by Experts

The correct Answer is:
C
`P=mv, v^(2)-u^(2)=2as, a =mu_(k)g`
Promotional Banner

Topper's Solved these Questions

  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - II (C.W)(MOTION OF BODY ON THE INCLINED PLANE)|8 Videos

  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - II (C.W)(PULLING/PUSHING A BODY)|3 Videos

  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - II (C.W)(EQUILIBRIUM OF A PARTICLE)|3 Videos

  • KINETIC THEORY OF GASES

    NARAYNA|Exercise LEVEL-III(C.W)|52 Videos

  • MATHEMATICAL REVIEW & PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|13 Videos

Similar Questions

Explore conceptually related problems

A vehicle of mass M is moving on a rough horizontal road with a momentum P If the coefficient of friction between the tyres and the road is mu is then the stopping distance is .

A vehicle of mass m is moving on a rough horizontal road with momentum P . If the coefficient of friction between the tyres and the road br mu, then the stopping distance is:

A car is moving along a straight horizontal road with a speed v_(0) . If the coefficient of friction between the tyres and the road is mu , the shortest distance in which the car can be stopped is

A car is moving along a straight horizontal road with a speed v_(0) . If the coefficient of friction between the tyre and the road is mu, the shortest distance in which the car can be stopped is.

An automobile is moving on a horizontal road with a speed upsilon If the coefficient of friction between the tyres and the road is mu show that the shortest distance in which the automobile can be stooped is upsilon^(2)//2 mu g .

Consider a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of static friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is [g=10 ms^(-1)]

Consider a car moving along a straight horizontal road with a speed of 72 km / h . If the coefficient of kinetic friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is [g=10ms^(-2)]

What is done to increase friction between the tyres and road ?