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A pulling force making an angle theta wi...

A pulling force making an angle `theta` with the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is `phi`, the magnitude of the force required to move the body is equal to

A

`(W Cos phi)/(Cos (theta-phi))`

B

`(W sin phi)/(Cos (theta-phi))`

C

`(Wtan phi)/(Sin(theta-phi))`

D

`(W Sin phi)/(Tan(theta-phi))`

Text Solution

Verified by Experts

The correct Answer is:
B
`N+P sin theta=mg, f =mu_(k)N`
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