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A person of mass 72kg sitting on ice pus...

A person of mass `72kg` sitting on ice pushes a block of mass of `30kg` on ice horizontally with a speed of `12ms^(-1)`.The coefficient of friction between the man and ice and between block and ice is `0.02`.If `g=10ms^(-1)`,the distance between man and the block,when they come to rest is

A

360m

B

10m

C

350m

D

422.5m

Text Solution

Verified by Experts

The correct Answer is:
D
`S_(1)=(v^(2))/(2mug)`, From L.C.M find `v^(1)`
`S_(2)=(v^(1^(2)))/(2mug),S=S_(1)+S_(2)`
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