Home
Class 11
PHYSICS
A block is sliding on a rough horizontal...

A block is sliding on a rough horizontal surface. If the contact force on the block is `sqrt2` times the frictional force, the coefficient of friction is

A

0.25

B

`(1)/(sqrt2)`

C

`sqrt2`

D

1

Text Solution

Verified by Experts

The correct Answer is:
D

`R=sqrt(N^(2)+f^(2)), N=mg`
Promotional Banner

Topper's Solved these Questions

  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - II (H.W)(MOTION OF A BODY ON THE INCLINED PLANE)|9 Videos
  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - II (H.W)(PULLING/PUSHING A BODY)|2 Videos
  • LAW OF MOTION

    NARAYNA|Exercise EXERCISE - II (H.W)(OBJECTS SUSPENDED BY STRINGS AND APPARENT WEIGHT)|16 Videos
  • KINETIC THEORY OF GASES

    NARAYNA|Exercise LEVEL-III(C.W)|52 Videos
  • MATHEMATICAL REVIEW & PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|13 Videos

Similar Questions

Explore conceptually related problems

A block of mass m is placed on a rough horizontal surface. If minimum force to pull the block is (mg)/(2) then coefficient of friction is :

A horizontal force of 20 N is applied to a block of 10 kg resting on a rough horizontal surface. How much additional force is required to just move the block, if the coefficient of static friction between the block and the surface is 0.4 ?

A wooden block of mass M resting on a rough horizontal surface is pulled with a force F at an angle  with the horizontal. If  is the coefficient of kinetic friction between the block and the surface, then acceleration of the block is -

A cubical block of side L rests on a rough horizonta surface with coefficient of friction mu . A horizontal force F is applied on the block as shown. If the coefficient of friction is sufficiently high so that the block does not slide before toppling, the minimum force required to topple the block is

A homogenous block of mass m, width b and height h is resting on a rough horizontal surface A horizontal force F is applied to it , which makes it to move with a constant velocity . The coefficient of friction between block and surface is mu Find the greatest height at which force F may be applied to slide the block with out tipping over

A block of mass 8 kg is placed on a rough horizontal plane. A time dependent force F=kt^2 acts on the block, where k=3N//s^2 . Coefficient of friction is 0.6 . Force of friction between the block and the plane at t=1s is

A block of mass 5kg is on a rough horizontal surface and is at rest. Now a force of 24 N is imparted to it with negligible impulse. If the coefficient of kinetic friction is 0.4 and g=9.8m//s^(2) , then the acceleration of the block is

A cubical block of side L rests on a rough horizontal surface with coefficient of friction mu . A horizontal force F is applied on the block as shown. If the coefficient of frictions sufficienty high so that the block does not slide before toppling, the minimum force required to topple the block is : .