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The pulley arrangements shown in figure are identical, the mass of the rope being negligible. In case I the mass m is lifted by attaching a mass `2m` to the other end of rope with a constant downward force `F =2mg`, where g is acceleration due to gravity The acceleration of mass m in case I is
.

A

Zero

B

More than that in case (b)

C

Less than that in case (b)

D

Equal to that is case (b)

Text Solution

Verified by Experts

The correct Answer is:
C
In case (a)
`T-mg=mA_(a)" …(i)"`
`2mg-T=2mA_(a)" …(ii)"`
Add (i) & (ii)
`A_(a)=g//3`
In case (b)
Tension in string `T_(b)=2mg`
`(because" Tension in uniform at every points in ideal string")`
`rArr" "A_(b)=(2mg)/(m)=2g rArr a_(b) gt A_(a)`
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