The coefficient of static friction, `mu_(s)` between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless.`(g=10m//s^(2))`

Options

A. 4.0 kg
B. 0.2 kg
C. 0.4 kg
D. 2.0 kg

Answer

C

Explanation

Let mass of block B is M

`T-f_(s)=0" ….(1) "T=Mg" …(3)"`
`N=2g" …(2)"`
By (1) & (3)
`f_(s)=Mg`
`because" "f_(s) le f_(s_("max"))`
`rArr" "Mg le u(N) rArrMgle u(2g)`
`M le 2u`
`rArr M le 0.4kg`