Four thin rods of same mass M and same length l, form a square as shown in figure. Moment of inertia of this system about an axis through centre O and perpendicular to its plane is

Explanation

`I = 4I_(CM) +4M (L/2)^(2) = 4 ((ML^(2))/12) + 4 (ML^(2))/4 = 4/3 ML^(2)`