A particle of mass 0.01 kg having position vector `vecr = ( 10 hati + 6 hatj)` meters is moving with a velocity `5 hati `m/s . Calculate its angular momentum about the origin.

Explanation

`vec(p) = mbr(v) = 0.01 xx5hat(i) = 0.05 hat(i)`
` :. ` Angular momentum
`vec (L) = bar(r ) xx bar(p) = (10 hat(i) +6hat(j)) xx 0.05 hat(i) = 0.3 hat(k) ` J/sec