A solid sphere rolls without slipping down a `30^(@)` inclined plane. If `g=10 ms^(-2)` then the acceleration of the rolling sphere is

Explanation

`alpha = (g sin theta)/beta = (g sin theta)/(1+I/(MR^(2))`
For a solid sphere : `I = 2/5 MR^(2)`
` :. A = (g sin 30^(@))/(1+2/5) = (10 xx1/2)/(7/5) = 5/7 xx5 = 25/7 "ms"^(-2)`