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A particle is moving in circular path wi...

A particle is moving in circular path with constant acceleration. In time t after the beginning of motion the direction of net acceleration is at `30^(@)` to the radius vector at that instant. The angular acceleration of the particle at that time t is

A

`3/(t^(2))`

B

`1/(t^(2))`

C

`(sqrt(3))/t`

D

`(sqrt(3))/(t^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
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