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A cord is wound round the circumference ...

A cord is wound round the circumference of wheel of radius `r`. The axis of the wheel is horizontal and fixed and moment of inertia about it is `I`. A weight `mg` is attached to the end of the cord and falls from rest. After falling through a distance `h`, the angular velocity of the wheel will be.

A

`sqrt((2gh)/(I+mr))`

B

`[(2mgh)/(I+mr^(2))] ^(1/2)`

C

` [(2mgh)/(I+2m)] ^(1/2)`

D

`sqrt(2gh)`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • A cord is wound round the circumference of wheel of radius r. The axis of the wheel is horizontal and moment of inertia about it is l. A weight mg is attached to the end of the cord and falls from rest. After falling through a distance h, the angular velocity of the wheel will be

    A
    `sqrt((2gh)/(I + mr))`
    B
    `sqrt((2mgh)/(I + mr^(2)))`
    C
    `sqrt((2mgh)/(I+ 2mr^(2)))`
    D
    `sqrt(2gh)`

  • A cord is wound around the circumference of wheel of radius r the axis of the wheel is horizontal and moment of inerita about it is / The weight mg is attached to the end of the cord and falls from rest after falling throgh a distance h the angular velocity of the wheel will be

    A
    `[mgh]^(1//2)`
    B
    `[(2mgh)/(I+2mr^(2))]^(1//2)`
    C
    `[(2mgh)/(I+mr^(2))]^(1//2)`
    D
    `[(mgh)/(I+2mr^(2))]^(1//2)`

  • A cord is wound round the circumference of wheel of radius r. The axis of the wheel is horizontal and the moment of inertia about it is I. A weight mg is attached to the cord at the end. The weight falls from rest. After falling through a distance 'h', the square of angular velocity of wheel will be :-

    A
    `(2mgh)/(I+2mr^(2))`
    B
    `(2mgh)/(I+mr^(2))`
    C
    2gh
    D
    `(2gh)/(I+mr^(2))`

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