The mass of a uniform circular ring of r...

The mass of a uniform circular ring of radius `0.2m` is `0.1kg`. Calcuate the moment of inertia of the ring about an axis passing through its centre an perpendicular to its surface.

`2xx10^(-3) "kg m"^(2)`

`3 xx10^(-3) " kg m"^(2)`

`4 xx10^(-3) " kg m"^(2)`

`1 xx10^(-3) " kg m"^(2)`

Text Solution

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The correct Answer is:

`I = mr^(2)`

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