If the radius of gyration of a solid dis...

If the radius of gyration of a solid disc of mass 10 kg about an axis is 0.40 m, then the moment of inertia of the disc about that axis is

`1.6 " kg m"^(2)`

`3.2 "kg m"^(2)`

`6.4 "kg m"^(2)`

`9.5 " kg m"^(2)`

Text Solution

Verified by Experts

The correct Answer is:

`K = sqrt(I/M) " " rArr I = K^(2) M `

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