A torque of 10 Nm is applied on a wheel ...

A torque of 10 Nm is applied on a wheel having angular momentum of `2 kg m^(2)s^(-1)`, calculate the angular momentum of the wheel after 4 seconds.

A

`42 " kg m"^(2)s^(-1)`

B

`30 "kg m"^(2)s^(-1)`

C

`80 "kg m"^(2)s^(-1)`

D

`18 "kg m"^(2)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:

A

`bar(tau) = (bar(L_(2))- bar(L)_(1))/t `
`bar(L)_(2) = bar(tau) t + bar(L)_(1) = 10 xx 4 +2 = 42 " Kgm"^(2)s^(-1)`

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