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A thin uniform circular ring is rolling ...

A thin uniform circular ring is rolling down an inclined plane of inclination `30^(@)` without slipping. Its linear acceleration along the inclined plane will be

A

g

B

`g/2`

C

`g/3`

D

`g/4`

Text Solution

Verified by Experts

The correct Answer is:
D
` a = (g sin theta )/(1+K^(2)//r^(2)) = g/(2(1+1)) = g/4 `
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NARAYNA-SYSTEM OF PARTICLES AND ROTATIONAL MOTION -EXERCISE - I (C.W)
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  16. A hollow sphere rolls down a 30^@ incline of length 6m without slippin...

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