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A thin circular ring first slips down a ...

A thin circular ring first slips down a smooth incline then rolls down a rough incline of identical geometry from same height. Ratio of time taken in the two motion is :

A

`1/2`

B

1

C

`1/(sqrt(2))`

D

`1/4`

Text Solution

Verified by Experts

The correct Answer is:
C
`t_(1) = sqrt((2h)/g ) , t_(2) = t_(1) sqrt(1+1 ) = t_(1) sqrt(2)`
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NARAYNA-SYSTEM OF PARTICLES AND ROTATIONAL MOTION -EXERCISE - I (C.W)
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  17. A ring and a disc of same mass roll without slipping along a horizonta...

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