Particles of masses 1kg and 3kg are at 2...

Particles of masses `1kg` and `3kg` are at `2i + 5j + 13k)m` and `(-6i + 4j - 2k)m` then instantaneous position of their centre of mass is

`1/4(-16 i + 17 j +7k)m `

`1/4 (-8i + 17 j + 7k) m `

`1/4 (-6i + 17 j + 7k) m `

`1/4 ( - 6i + 17 j + 5k)m`

Text Solution

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The correct Answer is:

`bar(r)_(cm) = (m_(1)barr_(1) +m_(2)bar(r)_(2))/(m_(1)m_(2))`

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NARAYNA-SYSTEM OF PARTICLES AND ROTATIONAL MOTION -EXERCISE - I(H.W)

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