If vec A= 3i + j +2k and vec B = 2i - 2j...

If `vec A= 3i + j +2k` and `vec B = 2i - 2j +4k` and `theta` is the angle between the two vectors, then `sin theta` is equal to

`2/3`

`2/(sqrt(3))`

`2/(sqrt(7))`

`2/(sqrt(13))`

Text Solution

Verified by Experts

The correct Answer is:

` sin theta = (|bar(A)xxbar(B)|)/(AB)`

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